已知T298.15K,p=100kPa,Δξ=1mol时,反应N2(g)+3H2(g)====2NH3(g)的 rHm=-92.22kJ·mol-1,计算相同条件下,下 已知T=298.15K,p=100kPa,Δξ=1mol时,反应N 2 (g)+3H 2 (g)====2NH 3 (g)的 r H m =-92.22kJ·mol -1 ,计算相同条件下,下列反应的 r H m 。
Transcribed image text 1. Write the equilibrium expression for the following reaction 2 points N2 g + 3H2 g 2NH3g 2. Calculate the equilibrium constant for the reaction below using the balanced chemical equation and the concentrations of the substances at equilibrium. 2 points N2g + 3H2g 2NH3 8 [N2] - M [H2] = M NH3 - M 3. Are reactants or products favored at equilibrium? 2 points 4. Calculate the equilibrium constant for the reaction below using the balanced chemical equation and the concentrations of the substances at equilibrium. 2 points N2 g + 3H2g 2NH3g [N2] M [H2] M NH3 - M 5. Compare your answers to Problems 2 & 4. Are your solutions to Problem 2 & 4 in agreement? 1 point Make a statement regarding the equilibrium constants you determined and the concentrations of substances at equilibrium. 1 point 5. Compare your answers to Problems 2 & 4. Are your solutions to Problem 2 & 4 in agreement? 1 point Make a statement regarding the equilibrium constants you determined and the concentrations of substances at equilibrium. 1 point Previous question Next questionJikatetapan kesetimbangan reaksi N2(g) + 3H2(g) = 2NH3(g) adalah K, tentukan tetapan kesetimbangan reaksi: - 25491495 Andysi5333 Andysi5333 15.11.2019 Kimia Sekolah Menengah Pertama terjawab • terverifikasi oleh ahli
2NH3的体积是(A)A.(V1V2V3)L B.(V1V2V3)L C.(V1V22V3)L D.V3(V1V2) L【解析】 N2 3H2 2NH3 V 1 3 2 2(V1V2V3)L根据比例即可得到答案。 ()C3H83H2O 3CO 7H2, COH2O=CO2H21mol 3mol 7mol 3mol 3mol1mol C3H8可生成10mol H2N2 3H2 2NH3 3 2 10mol (6.7mol)【题4】把氮气和氢气按:的物质的量比
KimiaFisik dan Analisis. Disajikan reaksi kesetimbangan berikut. N2 (g) + 3H2 (g) 2NH3 (g) deltaH = -22 kJ Pernyataan yang tepat mengenai reaksi kesetimbangan tersebut adalah Pergeseran Kesetimbangan dan Faktor-Faktor yang Mempengaruhinya.
Fora reaction, N2(g) + 3H2(g) + 2NH3(g) identify dihydrogen (H2) as a limiting reagent in the following reaction mixtures. (2019 Main, 9 April 1) (a) 56 g of N2 + 10 g of H, (b) 35 g of N2 + 8g of H, (c) 14 g of N2 + 4 g of H2 (d) 28 g of N2 +6g of H, < PreviousNext > Answer.
ColinVerified answer?? Not clear what you want! All these fit .. Take your choice. A) a reactant . B) only partly used as it is an equibria. C) reduced to ammonia 66GPDnT.